成功的ajax功能后，替换div中的内容

http://api.jquery.com/html/

 $.ajax({  type: "POST",  url: "scripts/process.php",  data: dataString,  success: function( returnedData ) {    $( '#container' ).html( returnedData );  } });

也使用http://api.jquery.com/load/，

$( '#container' ).load( 'scripts/process.php', { your: 'dataHereAsAnObjectWillMakeItUsePost' } );