我不确定为什么您说使用
cloneWithProps是一个不好的解决方案，但是这里是一个使用它的有效示例。
var Hello = React.createClass({ render: function() { return <div>Hello {this.props.name}</div>; }});var App = React.createClass({ render: function() { return ( <Group ref="buttonGroup"> <Button key={1} name="Component A"/> <Button key={2} name="Component B"/> <Button key={3} name="Component C"/> </Group> ); }});var Group = React.createClass({ getInitialState: function() { return { selectedItem: null }; }, selectItem: function(item) { this.setState({ selectedItem: item }); }, render: function() { var selectedKey = (this.state.selectedItem && this.state.selectedItem.props.key) || null; var children = this.props.children.map(function(item, i) { var isSelected = item.props.key === selectedKey; return React.addons.cloneWithProps(item, { isSelected: isSelected, selectItem: this.selectItem, key: item.props.key }); }, this); return ( <div> <strong>Selected:</strong> {this.state.selectedItem ? this.state.selectedItem.props.name : 'None'} <hr/> {children} </div> ); }});var Button = React.createClass({ handleClick: function() { this.props.selectItem(this); }, render: function() { var selected = this.props.isSelected; return ( <div onClick={this.handleClick} className={selected ? "selected" : ""} > {this.props.name} ({this.props.key}) {selected ? "<---" : ""} </div> ); }});React.renderComponent(<App />, document.body);这是一个jsFiddle演示它的运行情况。
编辑
：这是带有动态标签内容的更完整示例：jsFiddle
