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删除字符串中重复字符的功能

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

删除字符串中重复字符的功能

该功能对我来说很好。我已经写了内联评论。希望能帮助到你:

// function takes a char array as input.// modifies it to remove duplicates and adds a 0 to mark the end// of the unique chars in the array.public static void removeDuplicates(char[] str) {  if (str == null) return; // if the array does not exist..nothing to do return.  int len = str.length; // get the array length.  if (len < 2) return; // if its less than 2..can't have duplicates..return.  int tail = 1; // number of unique char in the array.  // start at 2nd char and go till the end of the array.  for (int i = 1; i < len; ++i) {     int j;    // for every char in outer loop check if that char is already seen.    // char in [0,tail) are all unique.    for (j = 0; j < tail; ++j) {      if (str[i] == str[j]) break; // break if we find duplicate.    }    // if j reachs tail..we did not break, which implies this char at pos i    // is not a duplicate. So we need to add it our "unique char list"    // we add it to the end, that is at pos tail.    if (j == tail) {      str[tail] = str[i]; // add      ++tail; // increment tail...[0,tail) is still "unique char list"    }  }  str[tail] = 0; // add a 0 at the end to mark the end of the unique char.}


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