程序在每个步骤执行的操作如下：
1 * 10 = 10 10 * 11 = 110 110 * 12 = 1320 1320 * 13 = 17160 17160 * 14 = 240240 240240 * 15 = 3603600 3603600 * 16 = 57657600 57657600 * 17 = 980179200 980179200 * 18 = 463356416 463356416 * 19 = 213837312 213837312 * 20 = -18221056 -18221056 * 21 = -382642176 -382642176 * 22 = 171806720 171806720 * 23 = -343412736 -343412736 * 24 = 348028928 348028928 * 25 = 110788608 110788608 * 26 = -1414463488-1414463488 * 27 = 464191488 464191488 * 28 = 112459776 112459776 * 29 = -1033633792-1033633792 * 30 = -944242688 -944242688 * 31 = 793247744 793247744 * 32 = -385875968 -385875968 * 33 = 150994944 150994944 * 34 = 838860800 838860800 * 35 = -704643072 -704643072 * 36 = 402653184 402653184 * 37 = 2013265920 2013265920 * 38 = -805306368 -805306368 * 39 = -1342177280-1342177280 * 40 = -2147483648-2147483648 * 41 = -2147483648-2147483648 * 42 =0 0 * 43 =0 0 * 44 =0vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv 0 * 97 =0 0 * 98 =0
请注意，在某些步骤上，相乘会导致较小的数字（980179200 * 18 = 463356416）或错误的符号（213837312 * 20 =
-18221056），表明存在整数溢出。但是零从何而来呢？继续阅读。
牢记
int数据类型是签署了32位，补整，这里是每一个步骤的说明：
Operation Result(1) Binary Representation(2) Result(3)---------------- ------------ ----------------------------------------------------------------- ------------ 1 * 10 10 1010 10 10 * 11110 1101110110 110 * 12 1320 10100101000 1320 1320 * 13 17160 100001100001000 17160 17160 * 14 240240 111010101001110000 240240 240240 * 15 3603600 1101101111110010010000 3603600 3603600 * 16 57657600 11011011111100100100000000 57657600 57657600 * 17 980179200 111010011011000101100100000000 980179200 980179200 * 18 17643225600 100 00011011100111100100001000000000 463356416 463356416 * 19 8803771904 10 00001100101111101110011000000000 213837312 213837312 * 20 4276746240 11111110111010011111100000000000 -18221056 -18221056 * 21 -382642176 11111111111111111111111111111111 11101001001100010101100000000000 -382642176 -382642176 * 22 -8418127872 11111111111111111111111111111110 00001010001111011001000000000000 171806720 171806720 * 23 3951554560 11101011100001111111000000000000 -343412736 -343412736 * 24 -8241905664 11111111111111111111111111111110 00010100101111101000000000000000 348028928 348028928 * 25 8700723200 10 00000110100110101000000000000000 110788608 110788608 * 26 2880503808 10101011101100010000000000000000 -1414463488-1414463488 * 27 -38190514176 11111111111111111111111111110111 00011011101010110000000000000000 464191488 464191488 * 28 12997361664 11 00000110101101000000000000000000 112459776 112459776 * 29 3261333504 11000010011001000000000000000000 -1033633792-1033633792 * 30 -31009013760 11111111111111111111111111111000 11000111101110000000000000000000 -944242688 -944242688 * 31 -29271523328 11111111111111111111111111111001 00101111010010000000000000000000 793247744 793247744 * 32 25383927808 101 11101001000000000000000000000000 -385875968 -385875968 * 33 -12733906944 11111111111111111111111111111101 00001001000000000000000000000000 150994944 150994944 * 34 51338280961 00110010000000000000000000000000 838860800 838860800 * 35 29360128000 110 11010110000000000000000000000000 -704643072 -704643072 * 36 -25367150592 11111111111111111111111111111010 00011000000000000000000000000000 402653184 402653184 * 37 14898167808 11 01111000000000000000000000000000 2013265920 2013265920 * 38 76504104960 10001 11010000000000000000000000000000 -805306368 -805306368 * 39 -31406948352 11111111111111111111111111111000 10110000000000000000000000000000 -1342177280-1342177280 * 40 -53687091200 11111111111111111111111111110011 10000000000000000000000000000000 -2147483648-2147483648 * 41 -88046829568 11111111111111111111111111101011 10000000000000000000000000000000 -2147483648-2147483648 * 42 -90194313216 11111111111111111111111111101011 00000000000000000000000000000000 0 0 * 43 00 0vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv 0 * 98 00 0
- 是 正确的 结果
- 是结果的内部表示形式（用于说明的是64位）
- 是由低32位的二进制补码表示的结果
我们知道，将数字乘以偶数：
- 向左移动位，向右添加零位
- 结果为偶数
因此，基本上，您的程序会反复将偶数与另一个数相乘，从而从右开始将结果位清零。
PS：如果乘法仅涉及奇数，则结果将不会为零。
