我如何迭代JSONObject以获得单个项目

您可以尝试这样做，它将在json对象中递归地找到所有键值，并构造为map。您只需从Map中获取所需的键即可。

public static Map<String,String> parse(JSonObject json , Map<String,String> out) throws JSONException{    Iterator<String> keys = json.keys();    while(keys.hasNext()){        String key = keys.next();        String val = null;        try{  JSonObject value = json.getJSonObject(key);  parse(value,out);        }catch(Exception e){ val = json.getString(key);        }        if(val != null){ out.put(key,val);        }    }    return out;} public static void main(String[] args) throws JSonException {    String json = "{'ipinfo': {'ip_address': '131.208.128.15','ip_type': 'Mapped','Location': {'continent': 'north america','latitude': 30.1,'longitude': -81.714,'CountryData': {'country': 'united states','country_pre': 'us'},'region': 'southeast','StateData': {'state': 'florida','state_pre': 'fl'},'CityData': {'city': 'fleming island','postal_pre': '32003','time_zone': -5}}}}";    JSonObject object = new JSonObject(json);    JSonObject info = object.getJSonObject("ipinfo");    Map<String,String> out = new HashMap<String, String>();    parse(info,out);    String latitude = out.get("latitude");    String longitude = out.get("longitude");    String city = out.get("city");    String state = out.get("state");    String country = out.get("country");    String postal = out.get("postal_pre");    System.out.println("Latitude : " + latitude + " LongiTude : " + longitude + " City : "+city + " State : "+ state + " Country : "+country+" postal "+postal);    System.out.println("ALL VALUE " + out);}

输出：

    Latitude : 30.1 LongiTude : -81.714 City : fleming island State : florida Country : united states postal 32003ALL VALUE {region=southeast, ip_type=Mapped, state_pre=fl, state=florida, country_pre=us, city=fleming island, country=united states, time_zone=-5, ip_address=131.208.128.15, postal_pre=32003, continent=north america, longitude=-81.714, latitude=30.1}