Xcode快速链接到Facebook页面

问题在于您的Facebook
URL的格式，因此请注意格式。我使用此扩展名打开网址。您以希望它们尝试打开的顺序为它提供了一组URL，它首先尝试第一个，如果失败，则转到第二个，依此类推：

extension UIApplication {    class func tryURL(urls: [String]) {        let application = UIApplication.sharedApplication()        for url in urls { if application.canOpenURL(NSURL(string: url)!) {     application.openURL(NSURL(string: url)!)     return }        }    }}

和使用：

UIApplication.tryURL([ "fb://profile/116374146706", // App "http://www.facebook.com/116374146706" // Website if app fails ])

Swift 4的[更新]：

extension UIApplication {    class func tryURL(urls: [String]) {        let application = UIApplication.shared        for url in urls { if application.canOpenURL(URL(string: url)!) {     application.openURL(URL(string: url)!)     return }        }    }}

然后：

UIApplication.tryURL(urls: [     "fb://profile/116374146706", // App     "http://www.facebook.com/116374146706" // Website if app fails     ])

[更新]适用于iOS 10 / Swift 5

extension UIApplication {    class func tryURL(urls: [String]) {        let application = UIApplication.shared        for url in urls { if application.canOpenURL(URL(string: url)!) {     if #available(iOS 10.0, *) {         application.open(URL(string: url)!, options: [:], completionHandler: nil)     }     else {         application.openURL(URL(string: url)!)     }     return }        }    }}