该程序打印以a
int为参数或返回a 的函数
int：
package mainimport ( "fmt" "reflect")func main() { funcs := make([]interface{}, 3, 3) // I use interface{} to allow any kind of func funcs[0] = func (a int) (int) { return a+1} // good funcs[1] = func (a string) (int) { return len(a)} // good funcs[2] = func (a string) (string) { return ":("} // bad for _, fi := range funcs { f := reflect.ValueOf(fi) functype := f.Type() good := false for i:=0; i<functype.NumIn(); i++ { if "int"==functype.In(i).String() { good = true // yes, there is an int among inputs break } } for i:=0; i<functype.NumOut(); i++ { if "int"==functype.Out(i).String() { good = true // yes, there is an int among outputs break } } if good { fmt.Println(f) } }}我认为代码是不言自明的
