栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 软件开发 > 后端开发 > Python

Python单链表实现、带尾结点的单链表实现

Python 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

Python单链表实现、带尾结点的单链表实现

一、单链表实现
# LList.py

class LNode:
    def __init__(self, elem, next_=None):
        self.elem = elem
        self.next = next_

class linkedListUnderUnderflow(ValueError):
    pass

class LList:
    def __init__(self) -> None:
        self.head = None

    # 判空
    def is_empty(self):
        return self.head is None
    
    # 表首插入
    def prepend(self, elem):
        self.head = LNode(elem, self.head)

    # 表首删除
    def pop(self):
        if self.head is None:
            raise linkedListUnderUnderflow("in pop")
        e = self.head.elem
        self.head = self.head.next

    # 遍历
    def for_each(self):
        temp_list = []
        p = self.head
        while p:
            temp_list.append(p.elem)
            p = p.next
        return temp_list
    
    # 后端操作
    def append(self, elem_):
        if self.head is None:
            self.head = LNode(elem_)
            return
        p = self.head
        while p.next:
            p = p.next
        p.next = LNode(elem_)
    
    # 删除最后一个元素
    def pop_last(self):
        if self.head is None:
            raise linkedListUnderUnderflow("in pop_last")
        if self.head.next is None:
            e = self.head.elem
            self.head = None
            return e
        p = self.head
        while p.next.next:
            p = p.next
        e = p.next.elem
        p.next = None
        return e

    # 逆转链表
    def reverse(self):
        new_queen = None
        while self.head:
            pointer = self.head
            self.head = pointer.next
            pointer.next = new_queen
            new_queen = pointer
        self.head = new_queen

if __name__ == '__main__':
    llist = LList()
    for value in range(10):
        llist.append(value)
    llist.pop_last()
    ret = llist.for_each()
    print(ret)
    llist.reverse()
    ret = llist.for_each()
    print(ret)
二、带为节点的单链表实现(继承自LList)
# LList1.py

from LList import *

class LList1(LList):
    def __init__(self) -> None:
        LList.__init__()
        self.rear = None
    
    # 前端插入
    def prepend(self, elem):
        if self.head:
            self.head = LNode(elem, self.head) 
        else:
            self.head = LNode(elem)
            self.rear = self.head
    
    # 后端插入
    def append(self, elem):
        if self.head is None:
            self.head = LNode(elem, self.head)
            self.rear = self.head
        else:
            self.rear.next = LNode(elem)
            self.rear = self.rear.next
    
    # 后端删除
    def pop_last(self):
        if self.head is None:
            raise linkedListUnderUnderflow("pop_last")
        p = self.head
        if p.next is None:
            e = self.head.elem
            self.head = None
            return e
        while p.next.next:
            p = p.next
        e = p.next.elem
        p.next = None
        self.rear = p
        return e


if __name__ == '__main__':
    llist = LList()
    for i in range(1, 11):
        llist.append(i)
    print(llist.for_each())
    print(llist.pop_last())
    print(llist.for_each())
转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/467917.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号