该题目特点：循环语句嵌套
技巧：从最内循环往外写
public class StringTest4 {
public static boolean getStr(String longStr,String shortStr){
boolean isFlag = false;
int cnt;
int shortFullLength = shortStr.length();
OUT:
for(cnt = 0;cnt < shortFullLength;cnt++){
//要获取到String的长度
int stringLength = shortFullLength-cnt;
//定义前后下标
int firstIndex;
int lastIndex;
//为前后下标找到数值
//定义容器
//装某个长度所有的String（以char[]的形式）
char str0[][] = new char[cnt + 1][stringLength];//长度为shortFullLength-cnt的字符串在字符串内一共有cnt+1个。
for (firstIndex = 0; firstIndex <= cnt; firstIndex++){
lastIndex = firstIndex+shortFullLength-cnt-1;//int stringLength = shortFullLength-cnt;
//要获取到String的长度
int string0 = lastIndex-firstIndex + 1;//int stringLength = shortFullLength-cnt;
//定义获取到String的char[]
int str0Index = 0;
//要获取的String长度为
for (int i = firstIndex; i <= lastIndex ; i++) {//获取一定长度的所有String,(在此循环中要获取的String已定)
//每次循环，获得一个char
str0[firstIndex][str0Index++] = shortStr.toCharArray()[i];
}
}
//把str0转化成String
String [] Stri0 = new String[cnt + 1];
for (int i = 0; i < cnt + 1; i++) {
Stri0[i] = new String(str0[i]);
}
for (int i = 0; i < Stri0.length;i++) {
if (longStr.contains(Stri0[i])) {
isFlag = true;
System.out.println("以下字符串符合要求："+Stri0[i]);
break OUT;
}
}
}
if(isFlag == false){
System.out.println("没有符合要求的字符串");
}
return isFlag;
}
public static void main(String[] args) {
StringTest4.getStr("abcwerthelloyuiodef", "cvhellobnm");
}
}
