Java正则表达式-捕获重复的组

Java不允许您访问重复捕获组的单个匹配项。

Tim Pietzcker提供的代码也可以为您提供帮助。如果您稍作修改，并为第一个数字添加特殊情况，则可以使用以下代码：

String target = "31,5,46,7,86";Pattern compileFirst = Pattern.compile("(?<number>[0-9]+)(,([0-9])+)*");Pattern compileFollowing = Pattern.compile(",(?<number>[0-9]+)");Matcher matcherFirst = compileFirst.matcher(target);Matcher matcherFollowing = compileFollowing.matcher(target);System.out.println("matches: " + matcherFirst.matches());System.out.println("first: " + matcherFirst.group("number"));int start = 0;while (matcherFollowing.find(start)) {    String group = matcherFollowing.group("number");    System.out.println("following: " + start + " - " + group);    start = matcherFollowing.end();}

输出：

matches: truefirst: 31following: 0 - 5following: 4 - 46following: 7 - 7following: 9 - 86