操纵/编辑现有xml文档的最佳Java Xml解析器

使用JDOM，获取InputStream并将其设为document：

InputStream inputStream = (InputStream)httpURLConnection.getContent();documentBuilderFactory docbf = documentBuilderFactory.newInstance();docbf.setNamespaceAware(true);documentBuilder docbuilder = docbf.newdocumentBuilder();document document = docbuilder.parse(inputStream, baseUrl);

那时，您在Java对象中具有XML。做完了 简单。

您既可以使用文档对象和Java API来遍历它，也可以使用XPath，我发现它很容易（一旦我了解了它）。

构建一个XPath对象，这需要一点时间：

public static XPath buildXPath() {    XPathFactory factory = XPathFactory.newInstance();    XPath xpath = factory.newXPath();    xpath.setNamespaceContext(new AtomNamespaceContext());    return xpath;}public class AtomNamespaceContext implements NamespaceContext {    public String getNamespaceURI(String prefix) {        if (prefix == null) throw new NullPointerException("Null prefix");        else if ("a".equals(prefix)) return "http://www.w3.org/2005/Atom";        else if ("app".equals(prefix)) return "http://www.w3.org/2007/app";        else if ("os".equals(prefix)) return "http://a9.com/-/spec/opensearch/1.1/";        else if ("x".equals(prefix))  return "http://www.w3.org/1999/xhtml";        else if ("xml".equals(prefix)) return XMLConstants.XML_NS_URI;        return XMLConstants.NULL_NS_URI;    }    // This method isn't necessary for XPath processing.    public String getPrefix(String uri) {        throw new UnsupportedOperationException();    }    // This method isn't necessary for XPath processing either.    public Iterator getPrefixes(String uri) {        throw new UnsupportedOperationException();    }}

然后只需使用它（幸运的是）根本不需要太多时间：

return Integer.parseInt(xpath.evaluate("/a:feed/os:totalResults/text()", document));