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将布尔表达式解析为PHP中的MySql查询

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将布尔表达式解析为PHP中的MySql查询

简单的查询生成器,假设PDO


        ## for simple tokenisation, the terms are separated by space here.        ## ###############################################################$string = "( C AND kernel ) OR ( C++ AND UML )";function emit_term( $tag ) {$res = " EXISTS (     SELECt *     FROM skill_usage su     JOIN skill_names sn ON sn.skill_id = su.skill_id     WHERe su.Job_id = j.job_id     AND sn.skillname = :" . $tag . ")n";return $res;}$fixed_part ="SELECt job_id, job_name FROM jobs j WHERe 1=1 AND n" ;# $tokens = explode( ' ' , $string ); #splits on any single space$tokens = preg_split( '/[s]+/' , $string ); # accepts multiple whitespace# print_r ( $tokens );$query = $fixed_part;$args = array();$num = 1;foreach ( $tokens as $tok ) {        switch ($tok) {        case '':  # skip empty tokens        case ';':  # No, you should not!        case '"':        case "'":        case ';':  break;        case '(': $query .= '('; break;        case ')': $query .= ')'; break;        case '&':        case 'AND': $query .= ' AND '; break;        case '|':        case 'OR': $query .= ' OR '; break;        case '!':        case 'NOT': $query .= ' NOT '; break;        default:     $tag = '_q' . $num ;     $query .= emit_term ( $tag );     $args[$tag] = $tok;     $num += 1;      break;     }        }$query .= ";nn";echo "Query + parameters (for PDO):n" ;echo $query;print_r ( $args) ;

输出:


SELECt job_id, job_name FROM jobs j WHERe 1=1 AND ( EXISTS (        SELECt *        FROM skill_usage su        JOIN skill_names sn ON sn.skill_id = su.skill_id        WHERe su.Job_id = j.job_id        AND sn.skillname = :_q1) AND  EXISTS (        SELECt *        FROM skill_usage su        JOIN skill_names sn ON sn.skill_id = su.skill_id        WHERe su.Job_id = j.job_id        AND sn.skillname = :_q2)) OR ( EXISTS (        SELECt *        FROM skill_usage su        JOIN skill_names sn ON sn.skill_id = su.skill_id        WHERe su.Job_id = j.job_id        AND sn.skillname = :_q3) AND  EXISTS (        SELECt *        FROM skill_usage su        JOIN skill_names sn ON sn.skill_id = su.skill_id        WHERe su.Job_id = j.job_id        AND sn.skillname = :_q4));Array(    [_q1] => C    [_q2] => kernel    [_q3] => C++    [_q4] => UML)


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