在Android中计算两次之间的差异

尝试下面的代码。

//假设时间格式为 （“ hh：mm a”） 格式

SimpleDateFormat simpleDateFormat = new SimpleDateFormat("hh:mm a");date1 = simpleDateFormat.parse("08:00 AM");date2 = simpleDateFormat.parse("04:00 PM");long difference = date2.getTime() - date1.getTime(); days = (int) (difference / (1000*60*60*24));  hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60)); min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);hours = (hours < 0 ? -hours : hours);Log.i("======= Hours"," :: "+hours);

输出 -小时数:: 8