#include
#include
void fish(int year, int month, int day);
void main()
{
int i, j;
int year, month, day;
int a[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
printf("请输入年月日n");
printf("年：");
scanf("%d", &year);
if (year > 1990)
printf("输入正确，你要查询的年分是%d年n", year);
else
{
printf("输入错误，请重新输入");
exit(0);
}
printf("月：");
scanf("%d", &month);
if(month>1&&month<13)
printf("输入正确，你要查询的月分是%d月n", month);
else
{
printf("输入错误，请重新输入");
exit(0);
}
printf("日：");
scanf("%d", &day);
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
{
if (month == 2)
{
if(day<30&&day>0)
printf("输入正确，你要查询的日子是%d日n", day);
else
{
printf("输入错误，请重新输入");
exit(0);
}
}
else
if(day>0&&day<32)
printf("输入正确，你要查询的日子是%d日n", day);
else
{
printf("输入错误，请重新输入");
exit(0);
}
}
fish(year, month, day);
}
void fish(int year, int month, int day)
{
int i, j;
int sum = 0;//n-1月的天数；
int t = 0;
int a[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };//为了方便计算，将a[0]省略；这样a[1]代表1月以此类推
for (i = 1990; i < year; i++)
{
if ((i % 4 == 0 && i % 100 != 0) || i % 400 == 0)
t++;//t代表闰年有几个，也代表多了几天；
}
printf("闰年有%d年n", t);
year = year - 1990-1;//注意还要减一，来计算天数；
month = month - 1;//方便计算天数；
for (i = 0;i
sum += a[i+1];
}
sum += day+t+year*365;
printf("总天数为：%dn", sum);
if (sum % 5 == 5 || sum % 5 == 4)
printf("晒网");
else
printf("打鱼");
}
