如何将Long转换为byte []并返回Java

public byte[] longToBytes(long x) {    ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES);    buffer.putLong(x);    return buffer.array();}public long bytesToLong(byte[] bytes) {    ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES);    buffer.put(bytes);    buffer.flip();//need flip     return buffer.getLong();}

或包装在一个类中，以避免重复创建

ByteBuffers

public class ByteUtils {    private static ByteBuffer buffer = ByteBuffer.allocate(Long.BYTES);        public static byte[] longToBytes(long x) {        buffer.putLong(0, x);        return buffer.array();    }    public static long bytesToLong(byte[] bytes) {        buffer.put(bytes, 0, bytes.length);        buffer.flip();//need flip         return buffer.getLong();    }}

由于它变得如此流行，我只想提一提，我认为在大多数情况下，最好使用像

Guava