栏目分类:
子分类:
返回
名师互学网用户登录
快速导航关闭
当前搜索
当前分类
子分类
实用工具
热门搜索
名师互学网 > IT > 面试经验 > 面试问答

SQL Server使用联合所有和分页

面试问答 更新时间: 发布时间: IT归档 最新发布 模块sitemap 名妆网 法律咨询 聚返吧 英语巴士网 伯小乐 网商动力

SQL Server使用联合所有和分页

尽管您还没有发布完整的查询,但是您可以尝试这样的操作

declare @columnSortNameDirection varchar(5);WITH resultSetCTE AS   (select ROW_NUMBER() OVER (        ORDER BY nr.is_read,nr.is_read_cashier,    CASE @columnSortNameDirection WHEN 'Pin' THEN r.name END ASC,    CASE @columnSortNameDirection WHEN 'PinDesc' THEN r.firstname END DESC  ) AS 'row_num',*  from (    SELECt        r.clave_receiver AS 'Pin',    r.id_branch AS 'Id_Branch',    r.id_receiver AS 'Id_receiver',      s.name_sender AS 'SenderFullName',    r.name_receiver AS 'ReceiverFullName',    r.id_flag_receiver AS  'Status',    pas.option_name AS 'ApprovalStatus',    r.mode_pay_receiver AS 'PaymentModeId'    UNIOn ALL    SELECT    r.clave_receiver AS 'Pin',    r.id_branch AS 'Id_Branch',    r.id_receiver AS 'Id_receiver',      s.name_sender AS 'SenderFullName',    r.name_receiver AS 'ReceiverFullName',    r.id_flag_receiver AS  'Status',    pas.option_name AS 'ApprovalStatus',    r.mode_pay_receiver AS 'PaymentModeId') as A )  Select *,  (SELECT COUNT(1) FROM resultSetCTE) AS 'RecordCount'  FROM resultSetCTE  WHERe row_num BETWEEN (1 - 1) * 15 + 1 AND 1 * 15   ORDER by IsRead,IsReadCashier


转载请注明:文章转载自 www.mshxw.com
本文地址:https://www.mshxw.com/it/441665.html
我们一直用心在做
关于我们 文章归档 网站地图 联系我们

版权所有 (c)2021-2022 MSHXW.COM

ICP备案号:晋ICP备2021003244-6号