var query = answers .GroupBy(a => a.answernumber, a => a, (k, g) => new {answernumber = k, Count = g.Count()}) .OrderyBy(i => i.answernumber);或另一种方式:
var query2 = from a in answers group a by a. answernumber into g orderby g.Key select new { answernumber = g.Key, Count = g.Count() };


