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如何在SQL Server 2005中选择最接近的匹配项?

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如何在SQL Server 2005中选择最接近的匹配项?

对于SQL Server 2005及更高版本,请尝试:

;WITH SalesScore AS (SELECt    s.PK_ID as S_PK        ,c.PK_ID AS c_PK        ,CASE   WHEN c.PK_ID IS NULL THEN 0  ELSE CASE WHEN s.ServiceId=c.ServiceId THEN 1 ELSE 0 END       +CASE WHEN (s.Address=c.Address AND s.Zip=c.Zip) THEN 1 ELSE 0 END       +CASE WHEN s.EmailAddress=c.EmailAddress THEN 1 ELSE 0 END       +CASE WHEN s.HomePhone=c.HomePhone THEN 1 ELSE 0 END         END AS Score    FROM Sales s        LEFT OUTER JOIN Customers c ON s.ServiceId=c.ServiceId      OR (s.Address=c.Address AND s.Zip=c.Zip)      OR s.EmailAddress=c.EmailAddress      OR s.HomePhone=c.HomePhone )SELECt     s.*,c.*    FROM (SELECt   S_PK,MAX(Score) AS Score   FROM SalesScore    GROUP BY S_PK         ) dt        INNER JOIN Sales          s ON dt.s_PK=s.PK_ID         INNER JOIN SalesScore    ss ON dt.s_PK=s.PK_ID AND dt.Score=ss.Score        LEFT OUTER JOIN Customers c ON ss.c_PK=c.PK_ID

编辑
我不愿在没有shema的情况下编写太多实际代码,因为我无法实际运行此代码并确保它能正常工作。但是,为了回答如何使用最后交易日期处理关系的问题,这是上述代码的较新版本:

;WITH SalesScore AS (SELECt    s.PK_ID as S_PK        ,c.PK_ID AS c_PK        ,CASE   WHEN c.PK_ID IS NULL THEN 0  ELSE CASE WHEN s.ServiceId=c.ServiceId THEN 1 ELSE 0 END       +CASE WHEN (s.Address=c.Address AND s.Zip=c.Zip) THEN 1 ELSE 0 END       +CASE WHEN s.EmailAddress=c.EmailAddress THEN 1 ELSE 0 END       +CASE WHEN s.HomePhone=c.HomePhone THEN 1 ELSE 0 END         END AS Score    FROM Sales s        LEFT OUTER JOIN Customers c ON s.ServiceId=c.ServiceId      OR (s.Address=c.Address AND s.Zip=c.Zip)      OR s.EmailAddress=c.EmailAddress      OR s.HomePhone=c.HomePhone )SELECt    *    FROM (SELECt    s.*,c.*,row_number() over(partition by s.PK_ID order by s.PK_ID ASC,c.LastTransaction DESC) AS RankValue   FROM (SELECt  S_PK,MAX(Score) AS Score  FROM SalesScore   GROUP BY S_PK        ) dt       INNER JOIN Sales          s ON dt.s_PK=s.PK_ID        INNER JOIN SalesScore    ss ON dt.s_PK=s.PK_ID AND dt.Score=ss.Score       LEFT OUTER JOIN Customers c ON ss.c_PK=c.PK_ID         ) dt2    WHERe dt2.RankValue=1


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