遍历* args？

获得 准确的 语法：

def userInput(ItemA, ItemB, *args):    THIS = ItemA    THAT = ItemB    MORE = args    print THIS,THAT,MOREuserInput('this','that','more1','more2','more3')

您将分配给

*

args``MORE``args``userInput

输出：

this that ('more1', 'more2', 'more3')

正如其他人所述，将其

args

def userInput(ItemA, ItemB, *args):        lst=[]    lst.append(ItemA)    lst.append(ItemB)    for arg in args:        lst.append(arg)    print ' '.join(lst)userInput('this','that','more1','more2','more3')

输出：

this that more1 more2 more3