您正在为每个电话的每个联系人打印那些“
FetchContacts”日志，因此，如果一个联系人为她存储了多个电话，您将看到它多次打印（即使它是相同的电话号码）。
如果您安装了类似Whatsapp的应用程序，那么几乎总是会看到每个联系人的所有电话号码重复，从而导致这些日志的打印次数超过每个联系人一次。
而且，这是通过电话获得联系的缓慢而痛苦的方式。取而代之的是，您可以直接通过Phones.CONTENT_URI直接查询并获取数据库中的所有电话，然后通过Contact-
ID将它们映射到联系人中：
Map<String, List<String>> contacts = new HashMap<String, List<String>>();String[] projection = { Phone.CONTACT_ID, Phone.DISPLAY_NAME, Phone.NUMBER };Cursor cur = cr.query(Phone.CONTENT_URI, projection, null, null, null);while (cur != null && cur.moveTonext()) { long id = cur.getLong(0); // contact ID String name = cur.getString(1); // contact name String data = cur.getString(2); // the actual info, e.g. +1-212-555-1234 Log.d(TAG, "got " + id + ", " + name + ", " + data); // add info to existing list if this contact-id was already found, or create a new list in case it's new String key = id + " - " + name; List<String> infos; if (contacts.containsKey(key)) { infos = contacts.get(key); } else { infos = new ArrayList<String>(); contacts.put(key, infos); } infos.add(data);}// contacts will now contain a mapping from id+name to a list of phones.// you can enforce uniqueness of phones while adding them to the list as well.
