LeetCode 71~75

本文隶属于专栏《LeetCode 刷题汇总》，该专栏为笔者原创，引用请注明来源，不足和错误之处请在评论区帮忙指出，谢谢！

本专栏目录结构请见LeetCode 刷题汇总

幕布链接

Java 10-lines solution with stack​

import scala.collection.mutable.ListBuffer

object Solution {
  def simplifyPath(path: String): String = {
    val paths = path.split("/")
    val res = ListBuffer[String]()
    for (p <- paths if p.nonEmpty && !p.equals(".")) {
      if (p.equals("..") && res.nonEmpty) res.remove(res.size - 1)
      else if (!p.equals("..")) res += p
    }
    "/" + res.mkString("/")
  }
}

class Solution {
    public String simplifyPath(String path) {
        Deque stack = new ArrayDeque<>();
        Set skip = new HashSet<>(Arrays.asList("..",".",""));
        for (String dir : path.split("/")) {
            if (dir.equals("..") && !stack.isEmpty()) stack.pop();
            else if (!skip.contains(dir)) stack.push(dir);
        }
        String res = "";
        for (String dir : stack) res = "/" + dir + res;
        return res.isEmpty() ? "/" : res;
    }
}

官方题解​

class Solution {
    public int minDistance(String word1, String word2) {
        int m = word1.length(), n = word2.length();
        if(m + n == 0) return 0;
        int[][] dp = new int[m + 1][n + 1];
        for(int i = 1; i <= m; i++){
            dp[i][0] = i;
        }
        for(int j = 1; j <= n; j++){
            dp[0][j] = j;
        }
        for(int i = 0; i < m; i++){
            for(int j = 0; j < n; j++){
                if(word1.charAt(i) == word2.charAt(j)){
                    dp[i + 1][j + 1] = dp[i][j];
                }else{
                    int insert = dp[i + 1][j];
                    int delete = dp[i][j + 1];
                    int replace = dp[i][j];
                    dp[i + 1][j + 1] = Math.min(Math.min(insert, delete), replace) + 1;
                }
            }
        }
        return dp[m][n];
    }
}

My AC java O(1) solution (easy to read)​

public class Solution {
    public void setZeroes(int[][] matrix) {
        boolean fr = false,fc = false;
        for(int i = 0; i < matrix.length; i++) {
            for(int j = 0; j < matrix[0].length; j++) {
                if(matrix[i][j] == 0) {
                    if(i == 0) fr = true;
                    if(j == 0) fc = true;
                    matrix[0][j] = 0;
                    matrix[i][0] = 0;
                }
            }
        }
        for(int i = 1; i < matrix.length; i++) {
            for(int j = 1; j < matrix[0].length; j++) {
                if(matrix[i][0] == 0 || matrix[0][j] == 0) {
                    matrix[i][j] = 0;
                }
            }
        }
        if(fr) {
            for(int j = 0; j < matrix[0].length; j++) {
                matrix[0][j] = 0;
            }
        }
        if(fc) {
            for(int i = 0; i < matrix.length; i++) {
                matrix[i][0] = 0;
            }
        }
    }
}

官方题解​

public class Solution {
    public boolean searchMatrix(int[][] matrix, int target) {
        if (matrix == null || matrix.length == 0) {
            return false;
        }
        int start = 0, rows = matrix.length, cols = matrix[0].length;
        int end = rows * cols - 1;
        while (start <= end) {
            int mid = (start + end) / 2;
            if (matrix[mid / cols][mid % cols] == target) {
                return true;
            } 
            if (matrix[mid / cols][mid % cols] < target) {
                start = mid + 1;
            } else {
                end = mid - 1;
            }
        }
        return false;
    }
}

官方题解

class Solution {
    public void sortColors(int[] A) {
       if(A==null || A.length<2) return;
       int low = 0; 
       int high = A.length-1;
       for(int i = low; i<=high;) {
           if(A[i]==0) {
              // swap A[i] and A[low] and i,low both ++
              int temp = A[i];
              A[i] = A[low];
              A[low]=temp;
              i++;low++;
           }else if(A[i]==2) {
               //swap A[i] and A[high] and high--;
              int temp = A[i];
              A[i] = A[high];
              A[high]=temp;
              high--;
           }else {
               i++;
           }
       }
   }
}