如何通过验证器获取有关无效DOM元素的更多信息？

如果使用Xerces（默认为Sun JDK），则可以通过http://apache.org/xml/properties/dom/current-
element-node
属性获取未通过验证的元素：

...catch (SAXParseException e){    Element curElement = (Element)validator.getProperty("http://apache.org/xml/properties/dom/current-element-node");    System.out.println("Validation error: " + e.getMessage());    System.out.println("Element: " + curElement);}

例：

String xml = "<root xmlns="http://www.myschema.org">n" +  "<text>This is text</text>n" +  "<number>32</number>n" +  "<number>abc</number>n" +  "</root>";documentBuilderFactory dbf = documentBuilderFactory.newInstance();dbf.setNamespaceAware(true);document doc = dbf.newdocumentBuilder().parse(new ByteArrayInputStream(xml.getBytes("UTF-8")));Schema schema = getSchema(getClass().getResource("myschema.xsd"));Validator validator = schema.newValidator();try{    validator.validate(new DOMSource(doc));}catch (SAXParseException e){    Element curElement = (Element)validator.getProperty("http://apache.org/xml/properties/dom/current-element-node");    System.out.println("Validation error: " + e.getMessage());    System.out.println(curElement.getLocalName() + ": " + curElement.getTextContent());    //Use curElement.getParentNode() or whatever you need here}