如何在枚举中使用Hibernate验证批注？

请注意，您还可以创建一个验证器来检查String是否为枚举的一部分。

public enum UserType { PERSON, COMPANY }@NotNull@StringEnumeration(enumClass = UserCivility.class)private String title;

@documented@Constraint(validatedBy = StringEnumerationValidator.class)@Target({ METHOD, FIELD, ANNOTATION_TYPE, PARAMETER, ConSTRUCTOR })@Retention(RUNTIME)public @interface StringEnumeration {  String message() default "{com.xxx.bean.validation.constraints.StringEnumeration.message}";  Class<?>[] groups() default {};  Class<? extends Payload>[] payload() default {};  Class<? extends Enum<?>> enumClass();}

public class StringEnumerationValidator implements ConstraintValidator<StringEnumeration, String> {  private Set<String> AVAILABLE_ENUM_NAMES;  @Override  public void initialize(StringEnumeration stringEnumeration) {    Class<? extends Enum<?>> enumSelected = stringEnumeration.enumClass();    //Set<? extends Enum<?>> enumInstances = EnumSet.allOf(enumSelected);    Set<? extends Enum<?>> enumInstances = Sets.newHashSet(enumSelected.getEnumConstants());    AVAILABLE_ENUM_NAMES = FluentIterable .from(enumInstances) .transform(PrimitiveGuavaFunctions.ENUM_TO_NAME) .toSet();  }  @Override  public boolean isValid(String value, ConstraintValidatorContext context) {    if ( value == null ) {      return true;    } else {      return AVAILABLE_ENUM_NAMES.contains(value);    }  }}

这很好，因为您不会丢失“错误值”的信息。您会收到类似的消息

值“ someBadUserType”不是有效的用户类型。有效的UserType值是：PERSON，COMPANY

编辑

对于那些想要非番石榴版本的人，应该使用类似以下的功能：

public class StringEnumerationValidator implements ConstraintValidator<StringEnumeration, String> {  private Set<String> AVAILABLE_ENUM_NAMES;  public static Set<String> getNamesSet(Class<? extends Enum<?>> e) {     Enum<?>[] enums = e.getEnumConstants();     String[] names = new String[enums.length];     for (int i = 0; i < enums.length; i++) {         names[i] = enums[i].name();     }     Set<String> mySet = new HashSet<String>(Arrays.asList(names));     return mySet;  }  @Override  public void initialize(StringEnumeration stringEnumeration) {    Class<? extends Enum<?>> enumSelected = stringEnumeration.enumClass();    AVAILABLE_ENUM_NAMES = getNamesSet(enumSelected);  }  @Override  public boolean isValid(String value, ConstraintValidatorContext context) {    if ( value == null ) {      return true;    } else {      return AVAILABLE_ENUM_NAMES.contains(value);    }  }}

并要自定义错误消息并显示适当的值，请检查以下内容：http://codingdict.com/questions/122937