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Flutter-如何在Firebase动态链接中为应用程序邀请功能传递自定义参数?

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Flutter-如何在Firebase动态链接中为应用程序邀请功能传递自定义参数?

使用动态链接的最佳方法是

import 'package:firebase_dynamic_links/firebase_dynamic_links.dart';import 'package:flutter/material.dart';class TestPage extends StatefulWidget {  @override  _TestPageState createState() => _TestPageState();}class _TestPageState extends State<TestPage> {  @override  void initState() {    super.initState();    fetchlinkData();  }  void fetchlinkData() async {    // FirebaseDynamiclinks.getInitiallink does a call to firebase to get us the real link because we have shortened it.    var link = await FirebaseDynamiclinks.instance.getInitiallink();    // This link may exist if the app was opened fresh so we'll want to handle it the same way onlink will.    handlelinkData(link);    // This will handle incoming links if the application is already opened    FirebaseDynamiclinks.instance.onlink(onSuccess: (PendingDynamiclinkData dynamiclink) async {      handlelinkData(dynamiclink);    });  }  void handlelinkData(PendingDynamiclinkData data) {    final Uri uri = data?.link;    if(uri != null) {      final queryParams = uri.queryParameters;      if(queryParams.length > 0) {        String userName = queryParams["username"];        // verify the username is parsed correctly        print("My users username is: $userName");      }    }  }  @override  Widget build(BuildContext context) {    return Scaffold(      appBar: AppBar(        title: Text("Sample"),      ),      body: Center(        child: Text("Test"),      ),      floatingActionButton: FloatingActionButton(        onPressed: () async {          var dynamiclink = await createDynamiclink(userName: "Test");          // dynamiclink has been generated. share it with others to use it accordingly.          print("Dynamic link: $dynamiclink");        },        child: Icon(          Icons.add,          color: Colors.white,        ),      ),    );  }  Future<Uri> createDynamiclink({@required String userName}) async {    final DynamiclinkParameters parameters = DynamiclinkParameters(      // This should match firebase but without the username query param      uriPrefix: 'https://test.page.link',      // This can be whatever you want for the uri, https://yourapp.com/groupinvite?username=$userName      link: Uri.parse('https://test.page.link/groupinvite?username=$userName'),      androidParameters: AndroidParameters(        packageName: 'com.test.demo',        minimumVersion: 1,      ),      iosParameters: IosParameters(        bundleId: 'com.test.demo',        minimumVersion: '1',        appStoreId: '',      ),    );    final link = await parameters.buildUrl();    final ShortDynamiclink shortenedlink = await DynamiclinkParameters.shortenUrl(      link,      DynamiclinkParametersOptions(shortDynamiclinkPathLength: ShortDynamiclinkPathLength.unguessable),    );    return shortenedlink.shortUrl;  }}

你完成了。



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