通过POST（ajax）发送JSON数据并从Controller（MVC）接收JSON响应

建立模型

public class Person{    public string Name { get; set; }    public string Address { get; set; }    public string Phone { get; set; }}

像下面的控制器

    public ActionResult PersonTest()    {        return View();    }    [HttpPost]    public ActionResult PersonSubmit(Vh.Web.Models.Person person)    {        System.Threading.Thread.Sleep(2000);                  return Json(new {msg="Successfully added "+person.Name });    }

Java脚本

<script type="text/javascript">    function send() {        var person = { name: $("#id-name").val(), address:$("#id-address").val(), phone:$("#id-phone").val()        }        $('#target').html('sending..');        $.ajax({ url: '/test/PersonSubmit', type: 'post', dataType: 'json', contentType: 'application/json', success: function (data) {     $('#target').html(data.msg); }, data: JSON.stringify(person)        });    }</script>