使用hibernate条件查询ManyToMany关系

这是我最终使用HQL实现它的方式：

public List<DriversLicence> findDriversLicencesWith(List<LicenceClass> licenceClasses) {    String hqlString = "select dl from DriversLicenceImpl dl where 1=1 ";    for (int i = 0; i < licenceClasses.size(); i++) {        hqlString += " and :licenceClass" + i + " = some elements(dl.licenceClasses)";    }    Query query = getSession().createQuery(hqlString);    for (int i = 0; i < licenceClasses.size(); i++) {        query.setParameter("licenceClass" + i, licenceClasses.get(i));    }    return query.list();}

或通过sqlRestriction使用Hibernate Criteria：

for (LicenceClass licenceClass : licenceClasses) {        criteria.add(Restrictions.sqlRestriction("? = some(select " + LicenceClass.PRIMARY_KEY + " from " +         LICENCE_CLASS_JOIN_TABLE + "  where {alias}." +         DriversLicence.PRIMARY_KEY + " = " + DriversLicence.PRIMARY_KEY + ")",         licenceClass.getId(), Hibernate.LONG));}

LICENCE_CLASS_JOIN_TABLE是hibernate生成的表的名称，该表支持driverLicence和LicenceClass之间的多对多关系。