C语言模拟实现memcpy

#include 
#include 

void* mymemcpy(void* dest, const void* str, size_t num) {
	assert(dest != NULL);
	assert(str != NULL);
	assert(num != 0);

	char* pp1 = (char*)dest;
	char* pp2 = (char*)str;

	for (int i = 0; i < num; i++) {
		pp1[i] = pp2[i];
	}
	return dest;
}

int main() {
	int p1[4] = { 1,2,3,4 };
	int p2[4] = { 0 };
	mymemcpy(p2, p1, sizeof(p1));
	for (int i = 0; i < 4; i++) {
		printf("%d ", p2[i]);
	}
	return 0;
}

实现结果：