使用C＃HttpListener进行URL映射

没有属性，您可以获得类似的效果

HttpListener listener = new HttpListener();listener.Prefixes.Add("http://*:8080/");listener.Start();while (true){    HttpListenerContext ctx = listener.GetContext();    ThreadPool.QueueUserWorkItem((_) =>    {        string methodName = ctx.Request.Url.Segments[1].Replace("/", "");        string[] strParams = ctx.Request.Url          .Segments          .Skip(2)          .Select(s=>s.Replace("/",""))          .ToArray();        var method = this.GetType().GetMethod(methodName);        object[] @params = method.GetParameters()      .Select((p, i) => Convert.ChangeType(strParams[i], p.ParameterType))      .ToArray();        object ret = method.Invoke(this, @params);        string retstr = JsonConvert.SerializeObject(ret);    });

用法是：

http://localhost:8080/getPersonHandler/333

如果您真的想使用属性，那么

HttpListener listener = new HttpListener();listener.Prefixes.Add("http://*:8080/");listener.Start();while (true){    HttpListenerContext ctx = listener.GetContext();    ThreadPool.QueueUserWorkItem((_) =>    {        string methodName = ctx.Request.Url.Segments[1].Replace("/", "");        string[] strParams = ctx.Request.Url          .Segments          .Skip(2)          .Select(s=>s.Replace("/",""))          .ToArray();        var method = this.GetType()      .GetMethods()      .Where(mi => mi.GetCustomAttributes(true).Any(attr => attr is Mapping && ((Mapping)attr).Map == methodName))      .First();        object[] @params = method.GetParameters()      .Select((p, i) => Convert.ChangeType(strParams[i], p.ParameterType))      .ToArray();        object ret = method.Invoke(this, @params);        string retstr = JsonConvert.SerializeObject(ret);    });}

然后，您可以使用as

http://localhost:8080/Person/333

class Mapping : Attribute{    public string Map;    public Mapping(string s)    {        Map = s;    }}[Mapping("Person")]public void getPersonHandler(int id){    Console.WriteLine("<<<<" + id);}