User.hasMany(Post, {foreignKey: 'user_id'})Post.belongsTo(User, {foreignKey: 'user_id'})Post.find({ where: { ...}, include: [User]})哪个会给你
SELECt `posts`.*, `users`.`username` AS `users.username`, `users`.`email` AS `users.email`, `users`.`password` AS `users.password`, `users`.`sex` AS `users.sex`, `users`.`day_birth` AS `users.day_birth`, `users`.`month_birth` AS `users.month_birth`, `users`.`year_birth` AS `users.year_birth`, `users`.`id` AS `users.id`, `users`.`createdAt` AS `users.createdAt`, `users`.`updatedAt` AS `users.updatedAt`FROM `posts` LEFT OUTER JOIN `users` AS `users` ON `users`.`id` = `posts`.`user_id`;
与您发布的内容相比，上面的查询可能看起来有些复杂，但是它所做的基本上只是为用户表的所有列添加别名，以确保在返回时将它们放置在正确的模型中，而不与发布模型混淆
除此之外，您还会注意到它执行JOIN而不是从两个表中进行选择，但是结果应该是相同的
进一步阅读：
- http://docs.sequelizejs.com/zh-CN/latest/docs/associations/#one-to-one-associations
- http://docs.sequelizejs.com/zh-CN/latest/docs/associations/#one-to-many-associations
- http://docs.sequelizejs.com/zh-CN/latest/docs/models-usage/#eager-loading
