使用jQuery从JavaScript对象添加/删除项目

首先，您引用的代码 不是
JSON。您的代码是Javascript对象文字表示法。JSON是为简化解析而设计的子集。

您的代码定义的对象（

data

items

id

name

type

您不需要或不需要jQuery，而只需Javascript。

添加项目：

data.items.push(    {id: "7", name: "Douglas Adams", type: "comedy"});

这增加了最后。参见下面的中间添加。

删除项目：

有几种方法。该

splice

data.items.splice(1, 3); // Removes three items starting with the 2nd,   // ("Witches of Eastwick", "X-Men", "Ordinary People")

splice

在中间添加：

splice

splice

removed_items = arrayObject.splice(index, num_to_remove[, add1[, add2[, ...]]]);

• index

  -开始进行更改的索引

• num_to_remove

  -从该索引开始，删除这么多条目

• addN

  -…然后插入这些元素

所以我可以在第3个位置添加一个项目，如下所示：

data.items.splice(2, 0,    {id: "7", name: "Douglas Adams", type: "comedy"});

这就是说：从索引2开始，删除零个项目，然后插入以下项目。结果看起来像这样：

var data = {items: [    {id: "1", name: "Snatch", type: "crime"},    {id: "2", name: "Witches of Eastwick", type: "comedy"},    {id: "7", name: "Douglas Adams", type: "comedy"},     // <== The new item    {id: "3", name: "X-Men", type: "action"},    {id: "4", name: "Ordinary People", type: "drama"},    {id: "5", name: "Billy Elliot", type: "drama"},    {id: "6", name: "Toy Story", type: "children"}]};

您可以删除并立即添加一些：

data.items.splice(1, 3,    {id: "7", name: "Douglas Adams", type: "comedy"},    {id: "8", name: "Dick Francis", type: "mystery"});

…这意味着：从索引1开始，删除三个条目，然后添加这两个条目。结果是：

var data = {items: [    {id: "1", name: "Snatch", type: "crime"},    {id: "7", name: "Douglas Adams", type: "comedy"},    {id: "8", name: "Dick Francis", type: "mystery"},    {id: "4", name: "Ordinary People", type: "drama"},    {id: "5", name: "Billy Elliot", type: "drama"},    {id: "6", name: "Toy Story", type: "children"}]};