从评论中悬挂
2020评论：现在，我们不再使用regex，而是
URLSearchParams为我们完成了所有这些工作，因此不再需要自定义代码，更不用说regex了。
我建议使用另一种正则表达式，使用子组分别捕获参数的名称和值：
function getUrlParams(url) { var re = /(?:?|&(?:amp;)?)([^=&#]+)(?:=?([^&#]*))/g, match, params = {}, depre = function (s) {return depreURIComponent(s.replace(/+/g, " "));}; if (typeof url == "undefined") url = document.location.href; while (match = re.exec(url)) { params[depre(match[1])] = depre(match[2]); } return params;}var result = getUrlParams("http://maps.google.de/maps?f=q&source=s_q&hl=de&geopre=&q=Frankfurt+am+Main&sll=50.106047,8.679886&sspn=0.370369,0.833588&ie=UTF8&ll=50.116616,8.680573&spn=0.35972,0.833588&z=11&iwloc=addr");result是一个对象：
{ f: "q" geopre: "" hl: "de" ie: "UTF8" iwloc: "addr" ll: "50.116616,8.680573" q: "Frankfurt am Main" sll: "50.106047,8.679886" source: "s_q" spn: "0.35972,0.833588" sspn: "0.370369,0.833588" z: "11"}正则表达式分解如下：
(?: # non-capturing group ?|& # "?" or "&" (?:amp;)? # (allow "&", for wrongly HTML-enpred URLs)) # end non-capturing group( # group 1 [^=&#]+ # any character except "=", "&" or "#"; at least once) # end group 1 - this will be the parameter's name(?: # non-capturing group =?# an "=", optional ( # group 2 [^&#]* # any character except "&" or "#"; any number of times ) # end group 2 - this will be the parameter's value) # end non-capturing group
