从另一个类启动JavaFX应用程序

我遇到了同样的问题，并使用此hack解决了这个问题：

import javafx.application.Application;import javafx.scene.Scene;import javafx.scene.control.Label;import javafx.scene.layout.BorderPane;import javafx.stage.Stage;import java.util.concurrent.CountDownLatch;public class StartUpTest extends Application {    public static final CountDownLatch latch = new CountDownLatch(1);    public static StartUpTest startUpTest = null;    public static StartUpTest waitForStartUpTest() {        try { latch.await();        } catch (InterruptedException e) { e.printStackTrace();        }        return startUpTest;    }    public static void setStartUpTest(StartUpTest startUpTest0) {        startUpTest = startUpTest0;        latch.countDown();    }    public StartUpTest() {        setStartUpTest(this);    }    public void printSomething() {        System.out.println("You called a method on the application");    }    @Override    public void start(Stage stage) throws Exception {        BorderPane pane = new BorderPane();        Scene scene = new Scene(pane, 500, 500);        stage.setScene(scene);        Label label = new Label("Hello");        pane.setCenter(label);        stage.show();    }    public static void main(String[] args) {        Application.launch(args);    }}

然后是您要从中启动应用程序的类：

public class StartUpStartUpTest {    public static void main(String[] args) {        new Thread() { @Override public void run() {     javafx.application.Application.launch(StartUpTest.class); }        }.start();        StartUpTest startUpTest = StartUpTest.waitForStartUpTest();        startUpTest.printSomething();    }}

希望对您有帮助。