使用Json.Net
string json = @"{ ""dc:creator"":""Jordan, Micheal"", ""element:publicationName"":""Applied Ergonomics"", ""element:issn"":""2839749823"" }";var pub = JsonConvert.DeserializeObject<Publication>(json);public class Publication{ [JsonProperty("dc:creator")] public string creator { set; get; } [JsonProperty("element:publicationName")] public string publicationName { set; get; } [JsonProperty("element:issn")] public string issn { set; get; }}要么
Console.WriteLine(JObject.Parse(json)["dc:creator"]);



