AJAX请求帮助下一页/上一页

尝试这样的事情…保持一个名为的全局变量，

currentPage

现场演示
http://jsfiddle.net/Jaybles/MawSB/

的HTML

<input id="next" type="button" value="Next" /><input id="prev" type="button" value="Previous" /> <div id="displayResults" name="displayResults">Current Page: 1</div>

JS

var currentPage=1;loadCurrentPage();$("#next, #prev").click(function(){    currentPage =         ($(this).attr('id')=='next') ? currentPage + 1 : currentPage - 1;    if (currentPage==0) //Check for min        currentPage=1;    else if (currentPage==101) //Check for max        currentPage=100;    else        loadCurrentPage();});function loadCurrentPage(){    $('input').attr('disabled','disabled'); //disable buttons    //show loading image    $('#displayResults').html('<img src="http://blog-well.com/wp-content/uploads/2007/06/indicator-big-2.gif" />');    $.ajax({        url: '/echo/html/',        data: 'html=Current Page: ' + currentPage+'&delay=1',        type: 'POST',        success: function (data) { $('input').attr('disabled',''); //re-enable buttons $('#displayResults').html(data); //Update Div        }    });}

然后，您的php页面可以相应地访问

$_REQUEST['page'];