在curl中将原始图像数据作为多部分/表单数据发布

如果任何人有同样的问题：检查这所建议@PravinS。我使用的代码与此处显示的完全相同，并且非常适合我。

这是服务器代码的相关部分，它有助于：

if (isset($_POST['btnUpload'])){$url = "URL_PATH of upload.php"; // e.g. http://localhost/myuploader/upload.php // request URL$filename = $_FILES['file']['name'];$filedata = $_FILES['file']['tmp_name'];$filesize = $_FILES['file']['size'];if ($filedata != ''){    $headers = array("Content-Type:multipart/form-data"); // cURL headers for file uploading    $postfields = array("filedata" => "@$filedata", "filename" => $filename);    $ch = curl_init();    $options = array(        CURLOPT_URL => $url,        CURLOPT_HEADER => true,        CURLOPT_POST => 1,        CURLOPT_HTTPHEADER => $headers,        CURLOPT_POSTFIELDS => $postfields,        CURLOPT_INFILESIZE => $filesize,        CURLOPT_RETURNTRANSFER => true    ); // cURL options    curl_setopt_array($ch, $options);    curl_exec($ch);    if(!curl_errno($ch))    {        $info = curl_getinfo($ch);        if ($info['http_pre'] == 200) $errmsg = "File uploaded successfully";    }    else    {        $errmsg = curl_error($ch);    }    curl_close($ch);}else{    $errmsg = "Please select the file";}}

html表单应类似于：

<form action="uploadpost.php" method="post" name="frmUpload" enctype="multipart/form-data"><tr>  <td>Upload</td>  <td align="center">:</td>  <td><input name="file" type="file" id="file"/></td></tr><tr>  <td>&nbsp;</td>  <td align="center">&nbsp;</td>  <td><input name="btnUpload" type="submit" value="Upload" /></td></tr>