有三种方法可以做到这一点；您可以
[XmlInclude]针对类型使用，也可以针对属性使用
XmlElement/
XmlArrayItem。它们都显示在下面；取消注释您喜欢的那对：
using System;using System.Collections.Generic;using System.Xml.Serialization;public class MyWrapper { //2: [XmlElement("A", Type = typeof(ChildA))] //2: [XmlElement("B", Type = typeof(ChildB))] //3: [XmlArrayItem("A", Type = typeof(ChildA))] //3: [XmlArrayItem("B", Type = typeof(ChildB))] public List<ChildClass> Data { get; set; }}//1: [XmlInclude(typeof(ChildA))]//1: [XmlInclude(typeof(ChildB))]public abstract class ChildClass { public string ChildProp { get; set; }}public class ChildA : ChildClass { public string AProp { get; set; }}public class ChildB : ChildClass { public string BProp { get; set; }}static class Program { static void Main() { var ser = new XmlSerializer(typeof(MyWrapper)); var obj = new MyWrapper { Data = new List<ChildClass> { new ChildA { ChildProp = "abc", AProp = "def"}, new ChildB { ChildProp = "ghi", BProp = "jkl"}} }; ser.Serialize(Console.Out, obj); }}
