我找到了答案，对于那些在这里寻找相同事物的人，我是怎么做的。您不应该考虑将图像上传到数据库，而是可以将上传文件的名称存储在数据库中，然后检索文件名，并在要显示图像的任何位置使用它。
HTML代码
<input type="file" name="imageUpload" id="imageUpload">
PHP代码
if(isset($_POST['submit'])) { //Process the image that is uploaded by the user $target_dir = "uploads/"; $target_file = $target_dir . basename($_FILES["imageUpload"]["name"]); $uploadOk = 1; $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION); if (move_uploaded_file($_FILES["imageUpload"]["tmp_name"], $target_file)) { echo "The file ". basename( $_FILES["imageUpload"]["name"]). " has been uploaded."; } else { echo "Sorry, there was an error uploading your file."; } $image=basename( $_FILES["imageUpload"]["name"],".jpg"); // used to store the filename in a variable //storind the data in your database $query= "INSERT INTO items VALUES ('$id','$title','$description','$price','$value','$contact','$image')"; mysql_query($query); require('heading.php'); echo "Your add has been submited, you will be redirected to your account page in 3 seconds...."; header( "Refresh:3; url=account.php", true, 303);}显示图像的代码
while($row = mysql_fetch_row($result)) { echo "<tr>"; echo "<td><img src='uploads/$row[6].jpg' height='150px' width='300px'></td>"; echo "</tr>n";}
