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使用ID代替对象填充SQLAlchemy多对多关系

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使用ID代替对象填充SQLAlchemy多对多关系

from sqlalchemy import *from sqlalchemy.orm import *from sqlalchemy.ext.declarative import declarative_basebase = declarative_base()class Person(base):    __tablename__ = 'person'    id      = Column(Integer, primary_key=True)    name    = Column(String(50))class SexyParty(base):    __tablename__ = 'sexy_party'    id      = Column(Integer, primary_key=True)    guests  = relationship('Person', secondary='guest_association',  lazy='dynamic', backref='parties')guest_association = Table(    'guest_association', base.metadata,    Column('user_id',       Integer(), ForeignKey('person.id'), primary_key=True),    Column('sexyparty_id',  Integer(), ForeignKey('sexy_party.id'), primary_key=True))e = create_engine("sqlite://", echo=True)base.metadata.create_all(e)sess = Session(e)p1 = Person(id=1, name='p1')p2 = Person(id=2, name='p2')p3 = Person(id=3, name='p3')p4 = Person(id=4, name='p4')sp1 = SexyParty(id=1)sess.add_all([sp1, p1, p2, p3, p4])sess.commit()# method one.  use insert()sess.execute(guest_association.insert().values([(1, 1), (2, 1)]))# method two.  map, optional association proxyfrom sqlalchemy.ext.associationproxy import association_proxyclass GuestAssociation(base):    __table__ = guest_association    party = relationship("SexyParty", backref="association_recs")SexyParty.association_ids = association_proxy(         "association_recs", "user_id",         creator=lambda uid: GuestAssociation(user_id=uid))sp1.association_ids.extend([3, 4])sess.commit()


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