试试这个
var form = $('#formId');$.ajax({ cache: false, async: true, type: "POST", url: form.attr('action'), data: form.serialize(), success: function (data) { alert(data); }});
试试这个
var form = $('#formId');$.ajax({ cache: false, async: true, type: "POST", url: form.attr('action'), data: form.serialize(), success: function (data) { alert(data); }});名师互学网 版权所有 (c)2021-2022 ICP备案号：晋ICP备2021003244-6号
