计算对象是否在一组坐标内？

您可以从这里开始：http :
//en.wikipedia.org/wiki/Point_in_polygon

您可能还会研究JTS拓扑套件。特别是使用此功能。

编辑 ：这是使用JTS的示例：

import java.util.ArrayList;import com.vividsolutions.jts.geom.Coordinate;import com.vividsolutions.jts.geom.GeometryFactory;import com.vividsolutions.jts.geom.LinearRing;import com.vividsolutions.jts.geom.Point;import com.vividsolutions.jts.geom.Polygon;import com.vividsolutions.jts.geom.impl.CoordinateArraySequence;public class GeoTest {  public static void main(final String[] args) {    final GeometryFactory gf = new GeometryFactory();    final ArrayList<Coordinate> points = new ArrayList<Coordinate>();    points.add(new Coordinate(-10, -10));    points.add(new Coordinate(-10, 10));    points.add(new Coordinate(10, 10));    points.add(new Coordinate(10, -10));    points.add(new Coordinate(-10, -10));    final Polygon polygon = gf.createPolygon(new LinearRing(new CoordinateArraySequence(points        .toArray(new Coordinate[points.size()])), gf), null);    final Coordinate coord = new Coordinate(0, 0);    final Point point = gf.createPoint(coord);    System.out.println(point.within(polygon));  }}

这是使用AWT的示例（它更简单，是Java SE的一部分）：

import java.awt.Polygon;public class JavaTest {  public static void main(final String[] args) {    final Polygon polygon = new Polygon();    polygon.addPoint(-10, -10);    polygon.addPoint(-10, 10);    polygon.addPoint(10, 10);    polygon.addPoint(10, -10);    System.out.println(polygon.contains(0, 0));  }}