如何在Java中排序对象？

您可以使用

Collections.sort(fileView)

Comparable

compareTo(fileObjarg0)

为了实施，

class fileObj implements Comparable<fileObj>@Override    public int compareTo(fileObj arg0) {        if(this.diffSeconds > arg0.diffSeconds )        return 0;        else return 1;    }

参考：

详细编码。

import java.util.ArrayList;import java.util.Collections;import java.util.Date;import java.util.List;public class SortExample {        public static void main(String[] args) {        // TODO Auto-generated method stub        List<fileObj> fileView = new ArrayList<fileObj>();        for(int j=0; j<10; j++)    {      fileView.add(new fileObj(j));    }        Collections.sort(fileView);        for(fileObj obj: fileView){ System.out.println("File " + obj.getDiffSeconds());        }    }}class fileObj implements Comparable<fileObj>{    public String fileName;     public Date modificationTime;     public long diffSeconds;    fileObj()    {        modificationTime = null;     }    fileObj(long diffSeconds)    {        modificationTime = null;        this.diffSeconds = diffSeconds;    }    @Override    public int compareTo(fileObj arg0) {        if(this.diffSeconds > arg0.diffSeconds )        return 0;        else return 1;    }    public long getDiffSeconds() {        return diffSeconds;    }    public void setDiffSeconds(long diffSeconds) {        this.diffSeconds = diffSeconds;    }}