这是我提出的解决方案。它基于蒂姆的建议，即比较后续角色的顺序。一些结果：
- jonas / jonax : 0.8
- jonas / sjona : 0.68
- jonas / sjonas : 0.66
- jonas / asjon : 0.52
- jonas / xxjon : 0.36
我确定我并不完美，并且可以对其进行优化，但是尽管如此，它似乎仍会产生我所追求的结果。一个弱点是，当字符串长度不同时，当字符串长度不同时，它会产生不同的结果。值被交换…
static public function string_compare($str_a, $str_b) { $length = strlen($str_a); $length_b = strlen($str_b); $i = 0; $segmentcount = 0; $segmentsinfo = array(); $segment = ''; while ($i < $length) { $char = substr($str_a, $i, 1); if (strpos($str_b, $char) !== FALSE) { $segment = $segment.$char; if (strpos($str_b, $segment) !== FALSE) { $segmentpos_a = $i - strlen($segment) + 1; $segmentpos_b = strpos($str_b, $segment); $positiondiff = abs($segmentpos_a - $segmentpos_b); $posfactor = ($length - $positiondiff) / $length_b; // <-- ? $lengthfactor = strlen($segment)/$length; $segmentsinfo[$segmentcount] = array( 'segment' => $segment, 'score' => ($posfactor * $lengthfactor)); } else { $segment = ''; $i--; $segmentcount++; } } else { $segment = ''; $segmentcount++; } $i++; } // PHP 5.3 lambda in array_map $totalscore = array_sum(array_map(function($v) { return $v['score']; }, $segmentsinfo)); return $totalscore; }
