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将两个表(具有1-M关系)联接在一起,其中第二个表需要“展平”到一行

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将两个表(具有1-M关系)联接在一起,其中第二个表需要“展平”到一行

select s.id,s.name,max(case when e.course_id = 55 then complete else null end) as c55,max(case when e.course_id = 66 then complete else null end) as c66,max(case when e.course_id = 77 then complete else null end) as c77from student as sleft join enrollment as eon s.id = e.student_idgroup by s.id

@克里斯。使用存储过程,您甚至可以在不知道列数的情况下创建动态数据透视表。这是链接

http://forum.html.it/forum/showthread.php?s=&threadid=1456236

我在一个意大利论坛上对类似问题的回答。有一个完整的示例可以帮助您了解背后的逻辑。:)

编辑。 使用MYSQL动态视图进行更新

这是我的开始转储:

drop table if exists `student`;create table `student` (  `id` int(10) unsigned not null auto_increment,  `name` varchar(50) default null,  primary key (`id`)) engine=myisam;insert  into `student`(`id`,`name`) values (1,'chris');insert  into `student`(`id`,`name`) values (2,'joe');insert  into `student`(`id`,`name`) values (3,'jack');drop table if exists enrollment;create table `enrollment` (  `enrollment_id` int(11) auto_increment primary key,  `student_id` int(11) default null,  `course_id` int(11) default null,  `complete` varchar(50) default null) engine=myisam auto_increment=8 default charset=latin1;insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (1,1,55,'true');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (2,1,66,'true');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (3,1,77,'true');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (4,2,55,'true');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (5,2,66,'false');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (6,3,55,'false');insert  into `enrollment`(`enrollment_id`,`student_id`,`course_id`,`complete`) values (7,3,66,'true');

这是动态视图的存储过程:

delimiter //drop procedure if exists dynamic_view//create procedure dynamic_view()begindeclare finish int default 0;declare cid int;declare str varchar(10000) default "select s.id,s.name,";declare curs cursor for select course_id from enrollment group by course_id;declare continue handler for not found set finish = 1;open curs;my_loop:loopfetch curs into cid;if finish = 1 thenleave my_loop;end if;set str = concat(str, "max(case when e.course_id = ",cid," then complete else null end) as course_",cid,",");end loop;close curs;set str = substr(str,1,char_length(str)-1);set @str = concat(str," from student as s left join enrollment as e on s.id = e.student_id group by s.id");prepare stmt from @str;execute stmt;deallocate prepare stmt;-- select str;end;//delimiter ;

现在叫它

mysql> call dynamic_view();+----+-------+-----------+-----------+-----------+| id | name  | course_55 | course_66 | course_77 |+----+-------+-----------+-----------+-----------+|  1 | chris | true      | true      | true      ||  2 | joe   | true      | false     | NULL      ||  3 | jack  | false     | true      | NULL      |+----+-------+-----------+-----------+-----------+3 rows in set (0.00 sec)Query OK, 0 rows affected (0.05 sec)

现在,我们插入另外两个具有两个不同课程的记录:

insert  into `enrollment`(`student_id`,`course_id`,`complete`) values (1,88,'true');insert  into `enrollment`(`student_id`,`course_id`,`complete`) values (3,99,'true');

我们回想一下程序。结果如下:

mysql> call dynamic_view();+----+-------+-----------+-----------+-----------+-----------+-----------+| id | name  | course_55 | course_66 | course_77 | course_88 | course_99 |+----+-------+-----------+-----------+-----------+-----------+-----------+|  1 | chris | true      | true      | true      | true      | NULL      ||  2 | joe   | true      | false     | NULL      | NULL      | NULL      ||  3 | jack  | false     | true      | NULL      | NULL      | true      |+----+-------+-----------+-----------+-----------+-----------+-----------+3 rows in set (0.00 sec)Query OK, 0 rows affected (0.02 sec)

就这样。:)



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