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SQL Server四舍五入问题,其中有5

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SQL Server四舍五入问题,其中有5

如果您确实想在SQL Server中使用银行取整…

CREATE FUNCTION BankersRounding(@value decimal(36,11), @significantDigits INT)        RETURNS MonEY        AS        BEGIN -- if value = 12.345 and signficantDigits = 2...    -- base = 1000 declare @base int = power(10, @significantDigits + 1)    -- roundingValue = 12345 declare @roundingValue decimal(36,11) = floor(abs(@value) * @base) -- roundingDigit = 5 declare @roundingDigit int = @roundingValue % 10    -- significantValue = 1234 declare @significantValue decimal(36,11) = floor(@roundingValue / 10) -- lastSignificantDigit = 4 declare @lastSignificantDigit int = @significantValue % 10    -- awayFromZero = 12.35 declare @awayFromZero money = (@significantValue + 1) / (@base / 10) -- towardsZero = 12.34 declare @towardsZero money = @significantValue / (@base / 10)    -- negative values handled slightly different if @value < 0 begin     -- awayFromZero = -12.35     set @awayFromZero = ((-1 * @significantValue) - 1) / (@base / 10)     -- towardsZero = -12.34     set @towardsZero = (-1 * @significantValue) / (@base / 10) end    -- default to towards zero (i.e. assume thousandths digit is 0-4) declare @rv money = @towardsZero if @roundingDigit > 5     set @rv = @awayFromZero  -- 5-9 goes away from 0 else if @roundingDigit = 5  begin     -- 5 goes to nearest even number (towards zero if even, away from zero if odd)     set @rv = case when @lastSignificantDigit % 2 = 0 then @towardsZero else @awayFromZero end end    return @rvend


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