这将为您提供帮助。我已经尝试使用您输入的双精度值之一-0.9913963644564902
public static void main(String[] args){ double d = 0.9913963644564902; System.out.println("0b"+Long.toBinaryString(Double.doubleToRawLongBits(d))); }输出将是
run:0b11111111101111101110011000010011011110010101101101100001110011BUILD SUCCESSFUL (total time: 0 seconds)



