以列表形式获取REST资源 与泽西岛

我找到了解决方案
https://java.net/projects/jersey/lists/users/archive/2011-08/message/37

public <T> List<T> getAll(final Class<T> clazz) {    ParameterizedType parameterizedGenericType = new ParameterizedType() {        public Type[] getActualTypeArguments() { return new Type[] { clazz };        }        public Type getRawType() { return List.class;        }        public Type getOwnerType() { return List.class;        }    };    GenericType<List<T>> genericType = new GenericType<List<T>>( parameterizedGenericType) {    };    return service.path(Path.ROOT).path(clazz.getSimpleName()) .accept(MediaType.APPLICATION_XML).get(genericType);}