您的课程
JSON_result与您的JSON字符串不匹配。请注意，该对象
JSON_result将如何表示，并包装在另一个名为中的属性中
"Venue"。
因此，要么为此创建一个类，例如：
Public Class Container Public Venue As JSON_resultEnd ClassPublic Class JSON_result Public ID As Integer Public Name As String Public NameWithTown As String Public NameWithDestination As String Public ListingType As StringEnd ClassDim obj = JsonConvert.DeserializeObject(Of Container)(...your_json...)
或将JSON字符串更改为
{ "ID": 3145, "Name": "Big Venue, Clapton", "NameWithTown": "Big Venue, Clapton, London", "NameWithDestination": "Big Venue, Clapton, London", "ListingType": "A", "Address": { "Address1": "Clapton Raod", "Address2": "", "Town": "Clapton", "County": "Greater London", "Postpre": "PO1 1ST", "Country": "United Kingdom", "Region": "Europe" }, "ResponseStatus": { "ErrorCode": "200", "Message": "OK" }}或使用例如a
ContractResolver解析JSON字符串。
