如何通过Swift中的URLScheme捕获用于启动OS X应用程序的URL？

据我从文档中得知，类采用常量并将其转换为正确的类型：

func applicationWillFinishLaunching(aNotification: NSNotification?) {    var appleEventManager:NSAppleEventManager = NSAppleEventManager.sharedAppleEventManager()    appleEventManager.setEventHandler(self, andSelector: "handleGetURLEvent:withReplyEvent:", forEventClass: AEEventClass(kInternetEventClass), andEventID: AEEventID(kAEGetURL))}