因此，根据我在此处找到的帖子，我整理了一个概念验证应用
它确实满足了我的要求-即使我仍然会分享我的解决方案。
#include <stdio.h>#include <stdlib.h>#include <string.h>#include <unistd.h>#include <errno.h>#include <fcntl.h>#include <dirent.h>#include <linux/input.h>#include <sys/types.h>#include <sys/stat.h>#include <sys/select.h>#include <sys/time.h>#include <termios.h>#include <signal.h>int main(int argc, char* argv[]){ struct input_event ev[64]; int fevdev = -1; int result = 0; int size = sizeof(struct input_event); int rd; int value; char name[256] = "Unknown"; char *device = "/dev/input/event3"; fevdev = open(device, O_RDONLY); if (fevdev == -1) { printf("Failed to open event device.n"); exit(1); } result = ioctl(fevdev, EVIOCGNAME(sizeof(name)), name); printf ("Reading From : %s (%s)n", device, name); printf("Getting exclusive access: "); result = ioctl(fevdev, EVIOCGRAB, 1); printf("%sn", (result == 0) ? "SUCCESS" : "FAILURE"); while (1) { if ((rd = read(fevdev, ev, size * 64)) < size) { break; } value = ev[0].value; if (value != ' ' && ev[1].value == 1 && ev[1].type == 1) { printf ("Code[%d]n", (ev[1].pre)); } } printf("Exiting.n"); result = ioctl(fevdev, EVIOCGRAB, 1); close(fevdev); return 0;}
