#since this was yesterdaydate -dyesterday +%Y%m%d#more precise, and more recommendeddate -d'27 JUN 2011' +%Y%m%d#assuming this is similar to yesterdays `date` question from you #http://stackoverflow.com/q/6497525/638649date -d'last-monday' +%Y%m%d#going on @seth's comment you could do thisDATE="27 jun 2011"; date -d"$DATE" +%Y%m%d#or a method to read it from stdinread -p " Get date >> " DATE; printf " AS YYYYMMDD format >> %s" `date-d"$DATE" +%Y%m%d`#which then outputs the following:#Get date >> 27 june 2011 #AS YYYYMMDD format >> 20110627#if you really want to use awkecho "27 june 2011" | awk '{print "date -d""$1FS$2FS$3"" +%Y%m%d"}' | bash#note | bash just redirects awk's output to the shell to be executed#FS is field separator, in this case you can use $0 to print the line#But this is useful if you have more than one date on a line有关日期的更多信息
请注意，这仅适用于GNU日期
我读过：
-d可以通过替换sunfreeware.com版本的日期来解决无法支持的Solaris版本的日期
